Butane reacts with oxygen to produce carbon dioxide and water following the equation given below. C 4 H 10 ( g )+13/2 O 2 ( g ) rightarrow 4 CO 2 ( g )+5 H 2 O ( I ) If 174.0 kg of butane is mixed with 320.0 kg of O 2 , the volume of water formed in liters is \ \ \ \ \ . (Nearest integer) [Given: (a) Molar mass of C, H, O are 12, 1, 16 g mol -1 respectively, (b) Density of water =1 g mL -1 ]

Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Main 2025 — 7 April, Evening Shift — Question 18

Butane reacts with oxygen to produce carbon dioxide and water following the equation given below.

$\mathrm{C}_{4} \mathrm{H}_{10}(\mathrm{~g})+\frac{13}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightarrow 4 \mathrm{CO}_{2}(\mathrm{~g})+5 \mathrm{H}_{2} \mathrm{O}(\mathrm{I})$

If 174.0 kg of butane is mixed with 320.0 kg of $\mathrm{O}_{2}$ , the volume of water formed in liters is $\_\_\_\_\_$ .

(Nearest integer)

[Given: (a) Molar mass of C, H, O are 12, 1, 16 g $\mathrm{mol}^{-1}$ respectively, (b) Density of water $=1 \mathrm{~g} \mathrm{~mL}^{-1}$ ]

Answer: 138

Numerical answer — enter this value.

Step-by-step solution

$\mathrm{C}_{4} \mathrm{H}_{10}(\mathrm{~g})+\frac{13}{2} \mathrm{O}_{2} \longrightarrow 4 \mathrm{CO}_{2}(\mathrm{~g})+5 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})$

Moles of $\mathrm{C}_{4} \mathrm{H}_{10}=\frac{174 \mathrm{~kg}}{50 \mathrm{~g}}=3 \times 10^{3}$

moles moles of $\mathrm{O}_{2}=\frac{320 \mathrm{~kg}}{32 \mathrm{~g}}$

$=10 \times 10^{3}$ moles

1 mole $\mathrm{C}_{4} \mathrm{H}_{10} \Rightarrow \frac{13}{2}$ moles $\mathrm{O}_{2}$

$3 \times 10^{3}$ moles $\mathrm{C}_{4} \mathrm{H}_{10} \Rightarrow \frac{13}{2} \times 3 \times 10^{3}{\text { mole } \mathrm{O}_{2}}$

$\mathrm{O}_{2}$ is limiting reagent

Moles of $\mathrm{H}_{2} \mathrm{O}$ formed $=\frac{10}{13} \times 5 \times 2 \times 10^{3}$

Volume of $\mathrm{H}_{2} \mathrm{O}$ formed $=\frac{10}{13} \times 5 \times 2 \times 18 \mathrm{~L}$

$=138.46 \mathrm{~L}$

Answer key and solution verified before publishing.

Practise Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free

Exam: JEE Main 2025
Paper: 7 April, Evening Shift
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic: Chemical Equations, Stoichiometry and Limiting Reagent