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Chemistry · Ionic Equilibrium

JEE Main 2025 — 22 January, Morning Shift — Question 41

Arrange the following solutions in order of their increasing boiling points.

(i) 10−4MNaCl10^{-4} \mathrm{M} \mathrm{NaCl}

(ii) 10−4M10^{-4} \mathrm{M} Urea

(iii) 10−3MNaCl10^{-3} \mathrm{M} \mathrm{NaCl}

(iv) 10−2MNaCl10^{-2} \mathrm{M} \mathrm{NaCl}

  1. Option A:

    (ii) < (i) < (iii) < (iv)

    Correct
  2. Option B:

    (( ii )<()<( i )≅() \cong( (iii )<()<( iv ))

  3. Option C:

    (i) << (ii) << (iii) << (iv)

  4. Option D:

    (iv) << (iii) << (i) << (ii)

Answer: A

Step-by-step solution

ΔTb=iKb.m.∝\Delta \mathrm{T}_{\mathrm{b}}=\mathrm{i} \mathrm{K}_{\mathrm{b}} . \mathrm{m} . \propto i.C.

where C=\mathrm{C}= concentration

Optionsi.C.
(i)2×10−42\times {{10}^{-4}}
(ii)1×10−41\times {{10}^{-4}}
(iii)2×10−32\times {{10}^{-3}}
(iv)2×10−22\times {{10}^{-2}}

B.P. order : (ii) << (i) << (iii) << (iv)

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
22 January, Morning Shift
Subject
Chemistry
Chapter
Ionic Equilibrium
Topic
pH of solution containing implicit reaction

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