Aqueous HCl reacts with MnO 2 ( s ) to form MnCl 2 ( aq ) , Cl 2 ( g ) and H 2 O (l) . What is the weight (in g ) of Cl 2 liberated when 8.7 g of MnO 2 ( s ) is reacted with excess aqueous HCl solution ? (Given Molar mass in g mol -1 Mn =55, Cl =35.5, O =16, H =1 )

Chemistry · Redox Reactions

JEE Main 2026 — 21 January, Evening Shift — Question 50

Aqueous HCl reacts with $\mathrm{MnO}_{2}(\mathrm{~s})$ to form $\mathrm{MnCl}_{2}(\mathrm{aq})$ , $\mathrm{Cl}_{2}(\mathrm{~g})$ and $\mathrm{H}_{2} \mathrm{O}(l)$ . What is the weight (in g ) of $\mathrm{Cl}_{2}$ liberated when 8.7 g of $\mathrm{MnO}_{2}(\mathrm{~s})$ is reacted with excess aqueous HCl solution ? (Given Molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{Mn}=55, \mathrm{Cl}=35.5, \mathrm{O}=16, \mathrm{H}=1$ )

Option A:
7.1
Correct
Option B:
71
Option C:
21.3
Option D:
14.2

Answer: A

Step-by-step solution

$\mathrm{MnO}_{2}+4 \mathrm{HCl} \rightarrow \mathrm{MnCl}_{2}+\mathrm{Cl}_{2}+2 \mathrm{H}_{2} \mathrm{O}$ $\frac{8.7}{87}$ Excess $=0.1$ mole 0.1 mole Wt. of $\mathrm{Cl}_{2}$ obtained $=0.1 \times 71=7.1 \mathrm{~g}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 21 January, Evening Shift
Subject: Chemistry
Chapter: Redox Reactions
Topic: n-Factor, Redox Titrations, Self Indicator & Miscellaneous Cases