Physics · Electrostatics

JEE Main 2024 — 1 February, Shift 2 — Question 42

$\mathrm{C}_{1}$ and $\mathrm{C}_{2}$ are two hollow concentric cubes enclosing charges 2 Q and 3 Q respectively as shown in figure. The ratio of electric flux passing through $\mathrm{C}_{1}$ and $\mathrm{C}_{2}$ is :

Option A:
$2: 5$
Correct
Option B:
$5: 2$
Option C:
$2: 3$
Option D:
$3: 2$

Answer: A

Step-by-step solution

$\quad \phi_{\text {smaller cube }}=\frac{2 Q}{\epsilon_{0}}$ $\phi_{\text {bigger cube }}=\frac{5 \mathrm{Q}}{\in_{0}}$ $\frac{\phi_{\text {smaller cube }}}{\phi_{\text {bigger cube }}}=\frac{2}{5}$

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Exam: JEE Main 2024
Paper: 1 February, Shift 2
Subject: Physics
Chapter: Electrostatics
Topic: Electric flux and Gauss's Law

Suppose a uniformly charged wall provides a uniform electric field of 2 × 10^4 N / C normally. A charged particle of mass 2 g being…

Answer: A

Step-by-step solution

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