An object with mass 500 g moves along x -axis with speed v=4 √(x) m / s . The force acting on the object is:

Physics · Motion in one Dimension

JEE Main 2025 — 7 April, Evening Shift — Question 59

An object with mass 500 g moves along $x$ -axis with speed $v=4 \sqrt{x} \mathrm{~m} / \mathrm{s}$ . The force acting on the object is:

Given:

v=4\sqrt{x}\ \text{m s}^{-1},\quad m=0.5\ \text{kg}

a=v\frac{dv}{dx}

\frac{dv}{dx}=\frac{4}{2\sqrt{x}}=\frac{2}{\sqrt{x}}

a=4\sqrt{x}\cdot\frac{2}{\sqrt{x}}=8\ \text{m s}^{-2}

F=ma=0.5\times 8=4\ \text{N}

Answer key and solution verified before publishing.

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.