An inductor of reactance 100 Ω , a capacitor of reactance 50 Ω , and a resistor of resistance 50 Ω are connected in series with an AC source of 10 V , 50 Hz . Average power dissipated by the circuit is W.

Physics · Alternating Current

JEE Main 2025 — 7 April, Evening Shift — Question 65

An inductor of reactance $100 \Omega$ , a capacitor of reactance $50 \Omega$ , and a resistor of resistance

$50 \Omega$ are connected in series with an AC source of $10 \mathrm{~V}, 50 \mathrm{~Hz}$ .

Average power dissipated by the circuit is $\qquad$ W.

Numerical answer — enter this value.

$P=\frac{I_{0} V_{0}}{2} \cos \phi$

\begin{aligned} & \cos \phi=\frac{R}{Z}, Z=\sqrt{R^{2}+\left(X_{L}-X_{C}\right)^{2}}=50 \sqrt{2} \Omega & \cos \phi=\frac{1}{2} \end{aligned}

P=1 W

Answer key and solution verified before publishing.

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