An ideal gas undergoes a cyclic transformation starting from the point A and coming back to the same point by tracing the path A rightarrow B rightarrow C rightarrow A as shown in the diagram. The total work done in the process is J.

Chemistry · Thermodynamics & Thermochemistry

JEE Main 2024 — 30 January, Shift 1 — Question 70

An ideal gas undergoes a cyclic transformation starting from the point A and coming back to the same point by tracing the path $\mathrm{A} \rightarrow \mathrm{B} \rightarrow \mathrm{C} \rightarrow \mathrm{A}$ as shown in the diagram. The total work done in the process is $\qquad$ J.

Answer: 200

Numerical answer — enter this value.

Step-by-step solution

Work done is given by area enclosed in the P vs V cyclic graph or V vs P cyclic graph.

Sign of work is positive for clockwise cyclic process for V vs P graph.

$\mathrm{W}=\frac{1}{2} \times(30-10) \times(30-10)=200 \mathrm{kPa}-\mathrm{dm}^{3}$

$=200 \times 1000 \mathrm{~Pa}-\mathrm{L}=2 \mathrm{~L}-$ bar $=200 \mathrm{~J}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 30 January, Shift 1
Subject: Chemistry
Chapter: Thermodynamics & Thermochemistry
Topic: Work Done in Different Cases