Physics · Thermodynamics

JEE Main 2026 — 5 April, Evening Shift — Question 9

An ideal gas at pressure P and temperature T is expanding such that PT3=constantPT^3 = \text{constant}. The coefficient of volume expansion of the gas is ____.

  1. Option A:

    2T\frac{2}{T}

  2. Option B:

    3T\frac{3}{T}

  3. Option C:

    4T\frac{4}{T}

    Correct
  4. Option D:

    3T\frac{3}{T}

Answer: C

Step-by-step solution

From PT3=CPT^3 = C and ideal gas PV=nRTPV = nRT, eliminate P: (nRT/V)T3=C⇒V∝T4 (nRT/V) T^3 = C \Rightarrow V \propto T^4. Then β=1VdVdT=4T\beta = \frac{1}{V}\frac{dV}{dT} = \frac{4}{T}.

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Physics
Chapter
Thermodynamics
Topic
First Law of Thermodynamics
An ideal gas at pressure P and temperature T is expanding such that… | JEE Main 2026 PYQ with Solution · DhiX AI