Physics · Electromagnetic Waves

JEE Main 2026 — 2 April, Evening Shift — Question 10

An electromagnetic wave travels in free space along the xx-direction. At a particular point in space and time, B⃗=2×10−7j^T\vec{B}=2\times10^{-7}\hat{j}\mathrm{T} is associated with this wave. The value of corresponding electric field E⃗\vec{E} at this point is V/m.

  1. Option A:

    60k^60\hat{k}

  2. Option B:

    −60k^-60\hat{k}

    Correct
  3. Option C:

    30k^30\hat{k}

  4. Option D:

    −600k^-600\hat{k}

Answer: B

Step-by-step solution

E⃗=B⃗×c⃗=(2×10−7j^)×(3×108i^)=−60k^V/m\vec{E}=\vec{B}\times\vec{c} = (2\times10^{-7}\hat{j})\times(3\times10^8\hat{i}) = -60\hat{k}\mathrm{V/m}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Physics
Chapter
Electromagnetic Waves
Topic
Displacement Current and Equation of EM Waves
An electromagnetic wave travels in free space along the x -direction.… | JEE Main 2026 PYQ with Solution · DhiX AI