Physics · Electrostatics

JEE Main 2025 — 29 January, Evening Shift — Question 19

An electric dipole is placed at a distance of 2 cm from an infinite plane sheet having positive charge

density σ0\sigma_{0}. Choose the correct option from the following.

Question figure
  1. Option A:

    Torque on dipole is zero and net force is directed away from the sheet.

  2. Option B:

    Torque on dipole is zero and net force acts towards the sheet.

  3. Option C:

    Potential energy of dipole is minimum and torque is zero.

    Correct
  4. Option D:

    Potential energy and torque both are maximum

Answer: C

Step-by-step solution

Here E=σ2ϵ0,τ⃗=P→×E→\mathrm{E}=\frac{\sigma}{2 \epsilon_{0}}, \vec{\tau}=\overrightarrow{\mathrm{P}} \times \overrightarrow{\mathrm{E}} τ⃗=0\vec{\tau}=0

U=−P→⋅E→U→\mathrm{U}=-\overrightarrow{\mathrm{P}} \cdot \overrightarrow{\mathrm{E}} \quad \mathrm{U} \rightarrow minimum

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Electrostatics
Topic
Electric Dipole