Physics · Newton's Laws of Motion

JEE Main 2024 — 4 April, Shift 1 — Question 56

An elastic spring under tension of 3 N has a length a. Its length is $b$ under tension 2 N . For its length $(3 a-2 b)$ , the value of tension will be $\qquad$ N

Answer: 5

Numerical answer — enter this value.

Step-by-step solution

$3=\mathrm{K}(\mathrm{a}-\ell)$ $2=\mathrm{K}(\mathrm{b}-\ell)$

$T=K(3 a-2 b-\ell)$

$T=K(3(a-\ell)-2(b-\ell)$

$=\mathrm{K}\left[3\left(\frac{3}{\mathrm{~K}}\right)-2\left(\frac{2}{\mathrm{~K}}\right)\right]$

$=9-4$

$=5 \mathrm{~N}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 4 April, Shift 1
Subject: Physics
Chapter: Newton's Laws of Motion
Topic: Spring Force and Combination of Springs