JEE Main 2024 — 8 April, Shift 2 — Question 52

$C=2 \mu \mathrm{f} ; \quad E=110 \sqrt{2} \sin (100 \mathrm{t})$

$X_{C}=\frac{1}{\omega c}=\frac{1}{100 \times 2 \times 10^{6}}$

$=\frac{10000}{2}=5000 \Omega$

$\mathrm{i}_{\mathrm{o}}=\frac{110 \sqrt{2}}{5000}$

$\mathrm{i}_{\mathrm{rms}}=\frac{110 \sqrt{2}}{5000 \sqrt{2}}$ $=\frac{110}{5} \mathrm{~mA}$

$=22 \mathrm{~mA}$