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Physics · Alternating Current

JEE Main 2025 — 4 April, Morning Shift — Question 60

An alternating current is represented by the equation, i=1002sin⁡(100πt)i=100 \sqrt{2} \sin (100 \pi t) ampere.

The RMS value of current and the frequency of the given alternating current are

  1. Option A:

    502 A,50 Hz50 \sqrt{2} \mathrm{~A}, 50 \mathrm{~Hz}

  2. Option B:

    1002 A,100 Hz100 \sqrt{2} \mathrm{~A}, 100 \mathrm{~Hz}

  3. Option C:

    100 A,50 Hz100 \mathrm{~A}, 50 \mathrm{~Hz}

    Correct
  4. Option D:

    1002 A,100 Hz\frac{100}{\sqrt{2}} \mathrm{~A}, 100 \mathrm{~Hz}

Answer: C

Step-by-step solution

i=1002sin⁡(100πt)i=100 \sqrt{2} \sin (100 \pi t)

irms =10022=100 A2πf=100πf=50 Hz\begin{aligned} & i_{\text {rms }}=\frac{100 \sqrt{2}}{\sqrt{2}}=100 \mathrm{~A} & 2 \pi f=100 \pi & f=50 \mathrm{~Hz} \end{aligned}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
4 April, Morning Shift
Subject
Physics
Chapter
Alternating Current
Topic
Average, Peak and RMS value of Alternating Current and Voltage
An alternating current is represented by the equation, i=100 √(2) sin… | JEE Main 2025 PYQ with Solution · DhiX AI