An ac current is represented as i=5 √(2)+10 cos (650 π t+π/6 ) Amp The r.m.s value of the current is

Physics · Alternating Current

JEE Main 2025 — 7 April, Morning Shift — Question 51

An ac current is represented as $i=5 \sqrt{2}+10 \cos \left(650 \pi t+\frac{\pi}{6}\right) \mathrm{Amp}$

The r.m.s value of the current is

$i=5 \sqrt{2}+10 \cos \left(650 \pi t+\frac{\pi}{6}\right)$

$i_{\text {RMS }}^{2}=I_{\text {(RMS })}^{2}+I_{2(\text { RMS })}^{2}$

$\Rightarrow \quad i_{(\text {RMS })}^{2}=50+\frac{100}{2}=100$

$\Rightarrow \quad i_{\mathrm{RMS}}=10 \mathrm{Amp}$

Answer key and solution verified before publishing.

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.