Chemistry · d and f Block Elements

JEE Main 2024 — 6 April, Shift 1 — Question 83

Among $\mathrm{CrO}, \mathrm{Cr}_{2} \mathrm{O}_{3}$ and $\mathrm{CrO}_{3}$ , the sum of spin-only magnetic moment values of basic and amphoteric oxides is $\qquad$ $10^{-2} \mathrm{BM}$ (nearest integer). (Given atomic number of Cr is 24 )

Answer: 877

Numerical answer — enter this value.

Step-by-step solution

CrO Basic oxide

$\mathrm{Cr}_{2} \mathrm{O}_{3}$ Amphoteric oxide

In $\mathrm{CrO}, \mathrm{Cr}$ exist as $\mathrm{Cr}^{+2}$ and have $\mu$ only $=4.90$

In $\mathrm{Cr}_{2} \mathrm{O}_{3}, \mathrm{Cr}$ exist as $\mathrm{Cr}^{+3}$ and have $\mu$ only $=3.87$

Sum of spin only magnetic moment

$=4.90+3.87=8.77$

$\mu_{\text {only }}=877 \times 10^{-2}$

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Exam: JEE Main 2024
Paper: 6 April, Shift 1
Subject: Chemistry
Chapter: d and f Block Elements
Topic: Compounds of Chromium

Answer: 877

Step-by-step solution

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