Physics · Current Electricity

JEE Main 2024 — 27 January, Shift 1 — Question 46

A wire of resistance R and length L is cut into 5 equal parts. If these parts are joined parallely, then resultant resistance will be :

  1. Option A:

    125R\frac{1}{25} \mathrm{R}

    Correct
  2. Option B:

    15R\frac{1}{5} R

  3. Option C:

    25 R

  4. Option D:

    5 R

Answer: A

Step-by-step solution

Resistance of each part =R5=\frac{R}{5} Total resistance =15×R5=R25=\frac{1}{5} \times \frac{\mathrm{R}}{5}=\frac{\mathrm{R}}{25}

Answer key and solution verified before publishing.

Practise Current Electricity

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Exam
JEE Main 2024
Subject
Physics
Chapter
Current Electricity
Topic
Ohm's Law and Calculation of Resistance
A wire of resistance R and length L is cut into 5 equal parts. If… | JEE Main 2024 PYQ with Solution · DhiX AI