A wheel is rolling on a plane surface. The speed of a particle on the highest point of the rim is 8 m / s . The speed of the particle on the rim of the wheel at the same level as the centre of wheel, will be

Physics · Rotational Dynamics

JEE Main 2025 — 4 April, Evening Shift — Question 50

A wheel is rolling on a plane surface. The speed of a particle on the highest point of the rim is $8 \mathrm{~m} / \mathrm{s}$ . The speed of the particle on the rim of the wheel at the same level as the centre of wheel, will be

Option A:
$8 \sqrt{2} \mathrm{~m} / \mathrm{s}$
Option B:
$4 \sqrt{2} \mathrm{~m} / \mathrm{s}$
Correct
Option C:
$8 \mathrm{~m} / \mathrm{s}$
Option D:
$4 \mathrm{~m} / \mathrm{s}$

Answer: B

Step-by-step solution

$V+\omega R=8$ $2 V=8$

V=4

V_{P}=\sqrt{2} V

=4 \sqrt{2}

Answer key and solution verified before publishing.

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Exam: JEE Main 2025
Paper: 4 April, Evening Shift
Subject: Physics
Chapter: Rotational Dynamics
Topic: Rolling Motion

A solid sphere with uniform density and radius R is rotating initially with constant angular velocity (omega 1 ) about its diameter. After…

Answer: B

Step-by-step solution

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