JEE Main 2026 — 24 January, Evening Shift — Question 47

Original mass (M) The removed mass (m) $\mathrm{m}=\rho \times \pi\left(\frac{\mathrm{R}}{3}\right)^{2} \times \frac{\mathrm{L}}{2}$ $=\frac{\rho \cdot \pi R^{2} L}{18}=\frac{M}{18}$ $\mathrm{I}^{\prime}=\frac{1}{2} \cdot \frac{\mathrm{M}}{18} \cdot \frac{\mathrm{R}^{2}}{9}=\frac{1}{324} \mathrm{MR}^{2}$ $\frac{\mathrm{I}}{\mathrm{I}^{\prime}}=\frac{\frac{1}{2} \mathrm{MR}^{2}}{\frac{1}{324} \mathrm{MR}^{2}}=162$