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Physics · Geometrical Optics

JEE Main 2025 — 28 January, Morning Shift — Question 66

A thin prism P_1 with angle 4^∘ made of glass having refractive index 1.54 , is combined with another thin prism P_2 made of glass having refractive index 1.72 to get dispersion without deviation. The angle of the prism P_2 in degrees is

  1. Option A:

    4

  2. Option B:

    3

    Correct
  3. Option C:

    16/3

  4. Option D:

    1.5

Answer: B

Step-by-step solution

δnet =0\delta_{\text {net }}=0

(μ1−1)A1−(μ2−1)A2=0\left(\mu_{1}-1\right) \mathrm{A}_{1}-\left(\mu_{2}-1\right) \mathrm{A}_{2}=0

(1.54−1)4−(1.72−1)A2=0(1.54-1) 4-(1.72-1) \mathrm{A}_{2}=0

A2=3∘\mathrm{A}_{2}=3^{\circ}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Paper
28 January, Morning Shift
Subject
Physics
Chapter
Geometrical Optics
Topic
Apparent Depth, Glass Slab, Prism and Dispersion

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