Chemistry · Practical Organic Chemistry

JEE Main 2026 — 28 January, Evening Shift — Question 64

A student has been given 0.314 g of an organic compound and asked to estimate Sulphur. During the experiment, the student has obtained 0.4813 g of barium sulphate. The percentage of sulphur present in the compound is ____\_\_\_\_。 (Given Molar mass in gmol−1 S:32,BaSO4:233\mathrm{g} \mathrm{mol}^{-1} \mathrm{~S}: 32, \mathrm{BaSO}_{4}: 233 )

  1. Option A:

    42.10%42.10 \%

  2. Option B:

    63.15%63.15 \%

  3. Option C:

    21.05%21.05 \%

    Correct
  4. Option D:

    48.24%48.24 \%

Answer: C

Step-by-step solution

%S\%S =32233×0.48130.314×100=\frac{32}{233} \times \frac{0.4813}{0.314} \times 100 =21.052%=21.052 \% Ans. (3) 21.05%21.05 \%

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Chemistry
Chapter
Practical Organic Chemistry
Topic
Quantitative organic analysis
A student has been given 0.314 g of an organic compound and asked to… | JEE Main 2026 PYQ with Solution · DhiX AI