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Physics · Mechanical Properties of Matter

JEE Main 2026 — 8 April, Evening Shift — Question 9

A spherical liquid drop of radius R acquires the terminal velocity v1v_1 when falls through a gas of viscosity η\eta. Now the drop is broken into 64 identical droplets and each droplet acquires terminal velocity v2v_2 falling through the same gas. The ratio of terminal velocities v1/v2v_1 / v_2 is

  1. Option A:

    4

  2. Option B:

    0.25

  3. Option C:

    32

  4. Option D:

    16

    Correct

Answer: D

Step-by-step solution

Volume conservation: 43πR3=64×43πr3\frac43\pi R^3 = 64\times\frac43\pi r^3 ⇒ r=R/4r = R/4. Terminal velocity v∝r2v \propto r^2, so v1/v2=(R/r)2=42=16v_1/v_2 = (R/r)^2 = 4^2 = 16.

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
8 April, Evening Shift
Subject
Physics
Chapter
Mechanical Properties of Matter
Topic
Viscosity
A spherical liquid drop of radius R acquires the terminal velocity v… | JEE Main 2026 PYQ with Solution · DhiX AI