Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Main 2024 — 29 January, Shift 1 — Question 77

A solution of H2SO4\mathrm{H_2SO_4} is 31.4%31.4\% H2SO4\mathrm{H_2SO_4} by mass and has a density of 1.25 g mL−11.25\ \mathrm{g\ mL^{-1}}. The molarity of the H2SO4\mathrm{H_2SO_4} solution is _____\_\_\_\_\_ MM (nearest integer).

[Given: molar mass of H2SO4=98 g mol−1\mathrm{H_2SO_4} = 98\ \mathrm{g\ mol^{-1}}]

Answer: 4

Numerical answer — enter this value.

Step-by-step solution

Assume 100 g100\ g solution.

Mass of H2SO4\mathrm{H_2SO_4} =31.4 g= \mathrm{31.4\ g}

Moles of H2SO4\mathrm{H_2SO_4} =31.498=0.32 mol= \mathrm{\frac{31.4}{98} = 0.32\ mol}

Volume of solution =1001.25=80 mL=0.08 L= \mathrm{\frac{100}{1.25} = 80\ mL = 0.08\ L}

Molarity, M=nsolute V\mathrm{M}=\frac{\mathrm{n}_{\text {solute }}}{\mathrm{V}}

M=0.320.08=4\mathrm{M = \frac{0.32}{0.08} = 4}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic
Concentration Terms and Their Interconversion
A solution of H 2SO 4 is 31.4\% H 2SO 4 by mass and has a density of… | JEE Main 2024 PYQ with Solution · DhiX AI