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Physics · Magnetism and Matter

JEE Main 2026 — 4 April, Evening Shift — Question 13

A solenoid has a core made of material with relative permeability 400. The magnetic field produced in the interior of solenoid is 1.0 T. The magnetic intensity in SI units is α×105\alpha \times 10^5. The value of α\alpha is ______.

  1. Option A:

    25π\frac{25}{\pi}

  2. Option B:

    116π\frac{1}{16\pi}

    Correct
  3. Option C:

    1π\frac{1}{\pi}

  4. Option D:

    14π\frac{1}{4\pi}

Answer: B

Step-by-step solution

H=Bμ0μr=14π×10−7×400=116π×105H = \frac{B}{\mu_0 \mu_r} = \frac{1}{4\pi\times10^{-7}\times400} = \frac{1}{16\pi}\times10^5. Thus α=116π\alpha = \frac{1}{16\pi}.

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
4 April, Evening Shift
Subject
Physics
Chapter
Magnetism and Matter
Topic
Magnetic Properties of Materials

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