A series LCR circuit is subjected to an AC signal of 200 V , 50 Hz . If the voltage across the inductor ( L =10 mH ) is 31.4 V , then the current in this circuit is :

Physics · Alternating Current

JEE Main 2024 — 5 April, Shift 2 — Question 40

A series LCR circuit is subjected to an AC signal of $200 \mathrm{~V}, 50 \mathrm{~Hz}$ . If the voltage across the inductor $(\mathrm{L}=10 \mathrm{mH})$ is 31.4 V , then the current in this circuit is $\qquad$ :

Option A:
68 A
Option B:
63 A
Option C:
10 A
Correct
Option D:
10 mA

Answer: C

Step-by-step solution

Voltage across inductor $\mathrm{V}_{\mathrm{L}}=\mathrm{IX}_{\mathrm{L}}$

\begin{aligned} & 31.4=\mathrm{I}[\mathrm{~L} \omega] & 31.4=\mathrm{I}[\mathrm{~L}(2 \pi \mathrm{f})] & 31.4=\mathrm{I}\left[10 \times 10^{-3}(2 \times 3.14) \times 50\right. & \Rightarrow \mathrm{I}=10 \mathrm{~A} \end{aligned}

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 5 April, Shift 2
Subject: Physics
Chapter: Alternating Current
Topic: Series LCR Circuit and Power Factor