Physics · Electrostatics

JEE Main 2026 — 4 April, Evening Shift — Question 11

A rigid dipole undergoes a simple harmonic motion about its centre in the presence of an electric field $\vec{E}_1 = E_0\hat{i}$ . If another electric field $\vec{E}_2 = 2E_0(\hat{y}+\hat{z})$ is introduced to the system, what will be the percentage change in the frequency of the oscillation (approximate)?

Option A:
0.73
Correct
Option B:
0.63
Option C:
0.83
Option D:
0.53

Answer: A

Step-by-step solution

Initial frequency $f_1 \propto \sqrt{E_0}$ . Final field magnitude $= \sqrt{E_0^2 + (2E_0)^2 + (2E_0)^2} = 3E_0$ . So $f_2/f_1 = \sqrt{3}$ . Percentage change = $(\sqrt{3}-1)\times100\% \approx 73.2\%$ .

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Exam: JEE Main 2026
Paper: 4 April, Evening Shift
Subject: Physics
Chapter: Electrostatics
Topic: Electric Dipole

Assertion A: In electrostatics, a conductor does not store any net charge inside. Reason R: Inside the capacitor (with no dielectric…

Answer: A

Step-by-step solution

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