Start free

Physics · Current Electricity

JEE Main 2026 — 24 January, Evening Shift — Question 29

A regular hexagon is formed by six wires each of resistance rΩ\mathrm{r} \Omega and the corners are joined to centre by wires of same resistance. If the current enters at one corner and leaves at the opposite corner, the equivalent resistance of the hexagon between the two opposite corners will be

  1. Option A:

    45r\frac{4}{5} \mathrm{r}

    Correct
  2. Option B:

    58r\frac{5}{8} \mathrm{r}

  3. Option C:

    34r\frac{3}{4} \mathrm{r}

  4. Option D:

    35r\frac{3}{5} \mathrm{r}

Answer: A

Step-by-step solution

Req =2R×4R32R+4R3=8R210R=45RR_{\text {eq }}=\frac{2 R \times \frac{4 R}{3}}{2 R+\frac{4 R}{3}}=\frac{8 R^{2}}{10 R}=\frac{4}{5} R

figure

figure

Solution figure

Answer key and solution verified before publishing.

Practise Current Electricity

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free
Exam
JEE Main 2026
Paper
24 January, Evening Shift
Subject
Physics
Chapter
Current Electricity
Topic
Combination of Resistors and cells, Wheatstone Bridge

More Current Electricity questions from this paper

A regular hexagon is formed by six wires each of resistance r Ω and… | JEE Main 2026 PYQ with Solution · DhiX AI