Physics · Electromagnetic Waves

JEE Main 2024 — 8 April, Shift 2 — Question 32

A plane progressive wave is given by y=2cos⁡2π(330t−x)my=2 \cos 2 \pi(330 t-x) m. The frequency of the wave is :

  1. Option A:

    165 Hz

  2. Option B:

    330 Hz

    Correct
  3. Option C:

    660 Hz

  4. Option D:

    340 Hz

Answer: B

Step-by-step solution

y=2cos⁡2π(330t−x)my=2 \cos 2 \pi(330 t-x) m

y=Acos⁡(ωt−kx)\mathrm{y}=\mathrm{A} \cos (\omega t-k x)

by comparing ω=2π×330\omega=2 \pi \times 330

2πf=2π×3302 \pi \mathrm{f}=2 \pi \times 330

f=330\mathrm{f}=330

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Physics
Chapter
Electromagnetic Waves
Topic
Displacement Current and Equation of EM Waves
A plane progressive wave is given by y=2 cos 2 π(330 t-x) m . The… | JEE Main 2024 PYQ with Solution · DhiX AI