Physics · Capacitors and R-C Circuits

JEE Main 2026 — 23 January, Evening Shift — Question 33

A parallel plate capacitor with plate separation 5 mm is charged by a battery. On introducing a mica sheet of 2 mm and maintaining the connections of the plates with the terminals of the battery, it is found that it draws 25%25 \% more charge from the battery. The dielectric constant of mica is ____\_\_\_\_ .

  1. Option A:

    2.5

  2. Option B:

    2

    Correct
  3. Option C:

    1.5

  4. Option D:

    1

Answer: B

Step-by-step solution

C=ϵ0AdC = \frac{\epsilon_0 A}{d} Q1=CVQ_1 = CV Q2=CeqVQ_2 = C_{\text{eq}} V Q2=1.25 CVQ_2 = 1.25\,CV Ceq=C1C2C1+C2=(ϵ0A3)(Kϵ0A2)(ϵ0A3)+(Kϵ0A2)C_{\text{eq}} = \frac{C_1 C_2}{C_1 + C_2} = \frac{\left(\frac{\epsilon_0 A}{3}\right) \left(\frac{K \epsilon_0 A}{2}\right)} {\left(\frac{\epsilon_0 A}{3}\right) + \left(\frac{K \epsilon_0 A}{2}\right)} Ceq=Kϵ02A26ϵ0A(2+3K)6C_{\text{eq}} = \frac{\frac{K \epsilon_0^2 A^2}{6}} {\frac{\epsilon_0 A (2 + 3K)}{6}} Ceq=Kϵ0A2+3KC_{\text{eq}} = \frac{K \epsilon_0 A}{2 + 3K} 1.25×ϵ0A5=Kϵ0A2+3K1.25 \times \frac{\epsilon_0 A}{5} = \frac{K \epsilon_0 A}{2 + 3K} 0.25(2+3K)=K0.25(2 + 3K) = K 2+3K=4K2 + 3K = 4K K=2K = 2

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Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Physics
Chapter
Capacitors and R-C Circuits
Topic
Effect of Dielectrics