A parallel plate capacitor has a capacitance C =200 pF . It is connected to 230 V ac supply with an angular frequency 300 rad / s . The rms value of conduction current in the circuit and displacement current in the capacitor respectively are :

Physics · Alternating Current

JEE Main 2024 — 1 February, Shift 1 — Question 36

A parallel plate capacitor has a capacitance $\mathrm{C}=200 \mathrm{pF}$ . It is connected to 230 V ac supply with an angular frequency $300 \mathrm{rad} / \mathrm{s}$ . The rms value of conduction current in the circuit and displacement current in the capacitor respectively are :

Option A:
$1.38 \mu \mathrm{~A}$ and $1.38 \mu \mathrm{~A}$
Option B:
$14.3 \mu \mathrm{~A}$ and $143 \mu \mathrm{~A}$
Option C:
$13.8 \mu \mathrm{~A}$ and $138 \mu \mathrm{~A}$
Option D:
$13.8 \mu \mathrm{~A}$ and $13.8 \mu \mathrm{~A}$
Correct

Answer: D

Step-by-step solution

$\mathrm{I}=\frac{\mathrm{V}}{\mathrm{X}_{\mathrm{C}}}=230 \times 300 \times 200 \times 10^{-12}=13.8 \mu \mathrm{~A}$

Answer key and solution verified before publishing.

Practise Alternating Current

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free

Exam: JEE Main 2024
Paper: 1 February, Shift 1
Subject: Physics
Chapter: Alternating Current
Topic: Average, Peak and RMS value of Alternating Current and Voltage

In series LCR circuit, the capacitance is changed from C to 4 C . To keep the resonance frequency unchanged, the new inductance should be :

Answer: D

Step-by-step solution

Practise Alternating Current

More Alternating Current questions from this paper