Chemistry · p-Block Elements (Group 15-18)

JEE Main 2026 — 5 April, Evening Shift — Question 65

A paper dipped in a dil. H2SO4\mathrm{H}_{2} \mathrm{SO}_{4} solution of ' X ' upon treatment with SO2\mathrm{SO}_{2} gas turns into green. The compound ' X ' is :

  1. Option A:

    KI-starch

  2. Option B:

    KMnO4\mathrm{KMnO}_{4}

  3. Option C:

    Pb(CH3COO)2\mathrm{Pb}\left(\mathrm{CH}_{3} \mathrm{COO}\right)_{2}

  4. Option D:

    K2Cr2O7\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}

    Correct

Answer: D

Step-by-step solution

SO2\mathrm{SO}_{2} gas acts as reducing agent.

K2Cr2O7+SO2→H2SO4Cr2 Green solution (SO4)3+SO42−\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}+\mathrm{SO}_{2} \xrightarrow{\mathrm{H}_{2} \mathrm{SO}_{4}} \underset{\text { Green solution }}{\mathrm{Cr}_{2}}\left(\mathrm{SO}_{4}\right)_{3}+\mathrm{SO}_{4}^{2-}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Chemistry
Chapter
p-Block Elements (Group 15-18)
Topic
Compounds of Sulphur - preparation and properties