A nucleus has mass number α and radius R α . Another nucleus has mass number β and radius R β . If β=8 α then R α / R β is :

Physics · Nuclear Physics

JEE Main 2026 — 28 January, Evening Shift — Question 26

A nucleus has mass number $\alpha$ and radius $R_{\alpha}$ . Another nucleus has mass number $\beta$ and radius $\mathrm{R}_{\beta}$ . If $\beta=8 \alpha$ then $R_{\alpha} / R_{\beta}$ is :

Option A:
2
Option B:
8
Option C:
1
Option D:
0.5
Correct

Answer: D

Step-by-step solution

$R_{\alpha}=R_{0} \alpha^{1 / 3}$ $R_{\beta}=R_{0} \beta^{1 / 3}$ $\frac{\mathrm{R}_{\alpha}}{\mathrm{R}_{\beta}}=\left(\frac{\alpha}{\beta}\right)^{1 / 3}=\frac{1}{2}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 28 January, Evening Shift
Subject: Physics
Chapter: Nuclear Physics
Topic: Introduction to Nucleus and its constituents