Physics · Electrostatics

JEE Main 2025 — 22 January, Morning Shift — Question 47

A line charge of length a ’ 2\frac{\mathrm{a} \text { ' }}{2} is kept at the center

of an edge BC of a cube ABCDEFGH having edge length ' aa ' as shown in the figure.

If the density of line is λC\lambda \mathrm{C} per unit length, then the total electric

flux through all the faces of the cube will be \qquad _. (Take, ϵ0\epsilon_{0} as the free space permittivity)

Question figure
  1. Option A:

    λa8ϵ0\frac{\lambda a}{8 \epsilon_{0}}

    Correct
  2. Option B:

    λa16ϵ0\frac{\lambda a}{16 \epsilon_{0}}

  3. Option C:

    λa2ϵ0\frac{\lambda a}{2 \epsilon_{0}}

  4. Option D:

    λa4ϵ0\frac{\lambda a}{4 \epsilon_{0}}

Answer: A

Step-by-step solution

Total charge inside the cube =λa24=λa8=\frac{\lambda \frac{\mathrm{a}}{2}}{4}=\frac{\lambda \mathrm{a}}{8} ∴ϕ=qin ε0=λa8ε0\therefore \phi=\frac{\mathrm{q}_{\text {in }}}{\varepsilon_{0}}=\frac{\lambda \mathrm{a}}{8 \varepsilon_{0}}

Answer key and solution verified before publishing.

Practise Electrostatics

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Exam
JEE Main 2025
Subject
Physics
Chapter
Electrostatics
Topic
Electric flux and Gauss's Law
A line charge of length frac a ' 2 is kept at the center of an edge… | JEE Main 2025 PYQ with Solution · DhiX AI