A light string passing over a smooth light fixed pulley connects two blocks of masses m 1 and m 2 . If the acceleration of the system is g / 8 , then the ratio of masses is

Physics · Newton's Laws of Motion

JEE Main 2024 — 31 January, Shift 2 — Question 29

A light string passing over a smooth light fixed pulley connects two blocks of masses $\mathrm{m}_{1}$ and $\mathrm{m}_{2}$ . If the acceleration of the system is $g / 8$ , then the ratio of masses is

Option A:
$\frac{9}{7}$
Correct
Option B:
$\frac{8}{1}$
Option C:
$\frac{4}{3}$
Option D:
$\frac{5}{3}$

Answer: A

Step-by-step solution

$\mathrm{a}=\frac{\left(\mathrm{m}_{1}-\mathrm{m}_{2}\right) \mathrm{g}}{\left(\mathrm{m}_{1}+\mathrm{m}_{2}\right)}=\frac{\mathrm{g}}{8}$

$8 \mathrm{~m}_{1}-8 \mathrm{~m}_{2}=\mathrm{m}_{1}+\mathrm{m}_{2}$

$7 \mathrm{~m}_{1}=9 \mathrm{~m}_{2}$

$\implies\frac{\mathrm{m}_{1}}{\mathrm{~m}_{2}}=\frac{9}{7}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 31 January, Shift 2
Subject: Physics
Chapter: Newton's Laws of Motion
Topic: Pulley - Block Problems