Physics · Capacitors and R-C Circuits

JEE Main 2024 — 1 February, Shift 2 — Question 45

A galvanometer $(\mathrm{G})$ of $2 \Omega$ resistance is connected in the given circuit. The ratio of charge stored in $\mathrm{C}_{1}$ and $\mathrm{C}_{2}$ is :

Option A:
$\frac{2}{3}$
Option B:
$\frac{3}{2}$
Option C:
1
Option D:
$\frac{1}{2}$
Correct

Answer: D

Step-by-step solution

In steady state $\operatorname{Req}=12 \Omega$ $\mathrm{I}=\frac{6}{12}=0.5 \mathrm{~A}$

P.D across $\mathrm{C}_{1}=3 \mathrm{~V}$ P.D acoross $\mathrm{C}_{2}=4 \mathrm{~V}$

$\mathrm{q}_{1}=\mathrm{C}_{1} \mathrm{~V}_{1}=12 \mu \mathrm{C}$

$\mathrm{q}_{2}=\mathrm{C}_{2} \mathrm{~V}_{2}=24 \mu \mathrm{C}$

$\frac{\mathrm{q}_{1}}{\mathrm{q}_{2}}=\frac{1}{2}$

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Exam: JEE Main 2024
Paper: 1 February, Shift 2
Subject: Physics
Chapter: Capacitors and R-C Circuits
Topic: Charging and Discharging of R-C Circuits

In an electrical circuit drawn below the amount of charge stored in the capacitor is \ \ \ \ \ \ \ mu C.

Answer: D

Step-by-step solution

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