Start free

Chemistry · Chemical Bonding

JEE Main 2024 — 31 January, Shift 2 — Question 72

A diatomic molecule has a dipole moment of 1.2 D. If the bond distance is 11Å, then fractional charge on each atom is \_\_\_\_\_\_\_\_$$\times {{10}^{-1}} esu .(Given 1D=10−181\text{D}={{10}^{-18}} esu cm )

Answer: 1.2

Numerical answer — enter this value.

Step-by-step solution

Given a diatomic molecule with dipole moment μ=1.2 D\mu = 1.2~\mathrm{D} and bond length r=1 A˚r = 1~\text{\AA}.

Step 1: Convert units:

μ=1.2 D=1.2×10−18 esu⋅cm,r=1 A˚=10−8 cm.\mu = 1.2~\mathrm{D} = 1.2 \times 10^{-18}~\mathrm{esu \cdot cm}, \quad r = 1~\text{\AA} = 10^{-8}~\mathrm{cm}.

Step 2: Fractional charge qq:

q=μr=1.2×10−1810−8=1.2×10−10 esu.q = \frac{\mu}{r} = \frac{1.2 \times 10^{-18}}{10^{-8}} = 1.2 \times 10^{-10}~\mathrm{esu}.

Step 3: Express in units of 10−110^{-1} esu:

q=1.2×10−10 esu=1.2×10−9×10−1 esu.q = 1.2 \times 10^{-10}~\mathrm{esu} = 1.2 \times 10^{-9} \times 10^{-1}~\mathrm{esu}. q=1.2×10−9 (10−1 esu)\boxed{q = 1.2 \times 10^{-9}~(10^{-1}~\mathrm{esu})}

Answer key and solution verified before publishing.

Practise Chemical Bonding

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free
Exam
JEE Main 2024
Paper
31 January, Shift 2
Subject
Chemistry
Chapter
Chemical Bonding
Topic
Dipole Moment and Fajans' Rule

More Chemical Bonding questions from this paper

A diatomic molecule has a dipole moment of 1.2 D. If the bond… | JEE Main 2024 PYQ with Solution · DhiX AI