A cubical block of density ρ b =600 kg / m 3 floats in a liquid of density ρ e =900 kg / m 3 . If the height of block is H=8.0 cm then height of the submerged part is \ \ \ \ cm.

Physics · Fluid Mechanics

JEE Main 2026 — 24 January, Evening Shift — Question 37

A cubical block of density $\rho_{\mathrm{b}}=600 \mathrm{~kg} / \mathrm{m}^{3}$ floats in a liquid of density $\rho_{e}=900 \mathrm{~kg} / \mathrm{m}^{3}$ . If the height of block is $H=8.0 \mathrm{~cm}$ then height of the submerged part is $\_\_\_\_$ cm.

Option A:
7.3
Option B:
4.3
Option C:
6.3
Option D:
5.3
Correct

Answer: D

Step-by-step solution

$\mathrm{Mg}=\mathrm{F}_{\mathrm{b}}$ $\mathrm{dAHg}=\rho \mathrm{Ahg}$ $600 \times 8 \mathrm{~cm}=900 \times \mathrm{h}$ $\mathrm{h}=\frac{16}{3} \mathrm{~cm}$ $\mathrm{h}=5.3 \mathrm{~cm}$

Answer key and solution verified before publishing.

Practise Fluid Mechanics

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free

Exam: JEE Main 2026
Paper: 24 January, Evening Shift
Subject: Physics
Chapter: Fluid Mechanics
Topic: Buoyancy and Archimedes' Principle