Physics · Geometrical Optics

JEE Main 2024 — 29 January, Shift 1 — Question 33

A convex mirror of radius of curvature 30 cm forms an image that is half the size of the object. The object distance is :

Answer: A

Given $\mathrm{R}=30 \mathrm{~cm}$

$\mathrm{f}=\mathrm{R} / 2=+15 \mathrm{~cm}$

Magnification $(\mathrm{m})= \pm \frac{1}{2}$

For convex mirror, virtual image is formed for real object. Therefore, $m$ is +ve $\frac{1}{2}=\frac{\mathrm{f}}{\mathrm{f}-\mathrm{u}}$

$\mathrm{u}=-15 \mathrm{~cm}$

Answer key and solution verified before publishing.

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