Physics · Mechanical Properties of Matter

JEE Main 2025 — 7 April, Evening Shift — Question 54

A capillary tube of radius 0.1 mm is partly dipped in water (surface tension 70dyn/cm70 \mathrm{dyn} / \mathrm{cm} and glass water contact angle ≈0∘\approx 0^{\circ} ) with 30∘30^{\circ} inclined with the vertical. The length of water risen in the capillary is \qquad cm . (Take g=9.8 m/s2g=9.8 \mathrm{~m} / \mathrm{s}^{2} )

  1. Option A:

    825\frac{82}{5}

    Correct
  2. Option B:

    685\frac{68}{5}

  3. Option C:

    715\frac{71}{5}

  4. Option D:

    572\frac{57}{2}

Answer: A

Step-by-step solution

h=2Tcos⁡θρgr=1007h=\frac{2 T \cos \theta}{\rho g r}=\frac{100}{7}

h′=hcos⁡θ=1007cos⁡30∘h^{\prime}=\frac{h}{\cos \theta}=\frac{100}{7 \cos 30^{\circ}}

h′=20073≈16.49≈825h^{\prime}=\frac{200}{7 \sqrt{3}} \approx 16.49 \approx \frac{82}{5} cm

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Mechanical Properties of Matter
Topic
Contact Angle and Capillarity
A capillary tube of radius 0.1 mm is partly dipped in water (surface… | JEE Main 2025 PYQ with Solution · DhiX AI