Mathematics · Permutations and Combinations

JEE Main 2026 — 5 April, Evening Shift — Question 33

A box contains 55 blue, 66 yellow and 44 red balls. The number of ways of drawing 88 balls containing at least two balls of each colour, is:

  1. Option A:

    41004100

    Correct
  2. Option B:

    41404140

  3. Option C:

    42304230

  4. Option D:

    42904290

Answer: A

Step-by-step solution

(But in this questions not mentioned that balls are distinct/alike)? Blue - 5 Yellow - 6 Red - 4 Reqd. No. of ways =5C2×6C2×4C4+5C2×6C3×4C3+5C2×6C4×4C2={ }^{5} \mathrm{C}_{2} \times{ }^{6} \mathrm{C}_{2} \times{ }^{4} \mathrm{C}_{4}+{ }^{5} \mathrm{C}_{2} \times{ }^{6} \mathrm{C}_{3} \times{ }^{4} \mathrm{C}_{3}+{ }^{5} \mathrm{C}_{2} \times{ }^{6} \mathrm{C}_{4} \times{ }^{4} \mathrm{C}_{2} +5C3×6C2×4C3+5C3×6C3×4C2+5C4×6C2×4C2+{ }^{5} \mathrm{C}_{3} \times{ }^{6} \mathrm{C}_{2} \times{ }^{4} \mathrm{C}_{3}+{ }^{5} \mathrm{C}_{3} \times{ }^{6} \mathrm{C}_{3} \times{ }^{4} \mathrm{C}_{2}+{ }^{5} \mathrm{C}_{4} \times{ }^{6} \mathrm{C}_{2} \times{ }^{4} \mathrm{C}_{2} =10×15×1+10×20×4+10×15×6+=10 \times 15 \times 1+10 \times 20 \times 4+10 \times 15 \times 6+ 10×15×4+10×20×6+5×15×610 \times 15 \times 4+10 \times 20 \times 6+5 \times 15 \times 6 =150+800+900+600+1200+450=150+800+900+600+1200+450 =4100=4100

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Permutations and Combinations
Topic
Combinations
A box contains 5 blue, 6 yellow and 4 red balls. The number of ways… | JEE Main 2026 PYQ with Solution · DhiX AI