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Physics · Gravitation

JEE Main 2026 — 5 April, Evening Shift — Question 7

A body of mass mm is taken from the surface of earth to a height equal to twice the radius of earth (R)(R). The increase in potential energy will be. (g is acceleration due to gravity at the surface of earth)

  1. Option A:

    12mgR\frac12 mgR

  2. Option B:

    34mgR\frac34 mgR

  3. Option C:

    14mgR\frac14 mgR

  4. Option D:

    23mgR\frac23 mgR

    Correct

Answer: D

Step-by-step solution

U1=−GMm/RU_1 = -GMm/R, U2=−GMm/(3R)U_2 = -GMm/(3R). ΔU=U2−U1=23GMmR=23mgR\Delta U = U_2-U_1 = \frac{2}{3}\frac{GMm}{R} = \frac{2}{3}mgR.

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Paper
5 April, Evening Shift
Subject
Physics
Chapter
Gravitation
Topic
Gravitational Potential Energy and Potential
A body of mass m is taken from the surface of earth to a height equal… | JEE Main 2026 PYQ with Solution · DhiX AI