Physics · Current Electricity

JEE Main 2026 — 21 January, Evening Shift — Question 34

A battery with EMF E and internal resistance $r$ is connected across a resistance $R$ . The power consumption in R will be maximum when :

Option A:
$R=2 r$
Option B:
$\mathrm{R}=\frac{\mathrm{r}}{2}$
Option C:
$R=\sqrt{2} r$
Option D:
$R=r$
Correct

Answer: D

Step-by-step solution

For maximum power drawn across load Resistance $R_{\text {Load }}=R_{\text {internal }}$

\mathrm{R}=\mathrm{r}

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 21 January, Evening Shift
Subject: Physics
Chapter: Current Electricity
Topic: Heating Effects of Current and Thermal Powe

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