Physics · Alternating Current

JEE Main 2024 — 4 April, Shift 1 — Question 52

A alternating current at any instant is given by i=[6+56sin⁡(100πt+π3)]\mathrm{i}=\left[6+\sqrt{56} \sin \left(100 \pi \mathrm{t}+\frac{\pi}{3}\right)\right] A. The rms value of the current

is \qquad A.

Answer: 8

Numerical answer — enter this value.

Step-by-step solution

I_{r m s}=\sqrt{\frac{\int i^{2} d t}{\int d t}}$

Irms=(6)2+(56)22I_{\mathrm{rms}}=\sqrt{(6)^{2}+\frac{(\sqrt{56})^{2}}{2}}

=36+28=\sqrt{36+28}

=64=\sqrt{64}

=8 A=8 \mathrm{~A}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Physics
Chapter
Alternating Current
Topic
Average, Peak and RMS value of Alternating Current and Voltage
A alternating current at any instant is given by i = [6+√(56) sin… | JEE Main 2024 PYQ with Solution · DhiX AI