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Chemistry · Redox Reactions

JEE Main 2026 — 28 January, Morning Shift — Question 60

500 mL of 1.2 M KI solution is mixed with 500 mL of 0.2MKMnO40.2 \mathrm{M} \mathrm{KMnO}_{4} solution in basic medium. The liberated iodine was titrated with standard 0.1MNa2 S2O30.1 \mathrm{M} \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3} solution in the presence of starch indicator till the blue color disappeared. The volume (in L ) of Na2 S2O3\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3} consumed is ____\_\_\_\_ . (Nearest integer)

Answer: 3

Numerical answer — enter this value.

Step-by-step solution

MnO4−+I−→MnO2+I2\mathrm{MnO}_{4}^{-}+\mathrm{I}^{-} \rightarrow \mathrm{MnO}_{2}+\mathrm{I}_{2} I2+S2O32−→S4O62−+I−\mathrm{I}_{2}+\mathrm{S}_{2} \mathrm{O}_{3}{ }^{2-} \rightarrow \mathrm{S}_{4} \mathrm{O}_{6}{ }^{2-}+\mathrm{I}^{-} gram eq of KMnO4=\mathrm{KMnO}_{4}= gram eq of Na2 S2O3\mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3} 0.2×5001000×3=0.1×V×10.2 \times \frac{500}{1000} \times 3=0.1 \times \mathrm{V} \times 1 V=3 L\mathrm{V}=3 \mathrm{~L}

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Exam
JEE Main 2026
Paper
28 January, Morning Shift
Subject
Chemistry
Chapter
Redox Reactions
Topic
n-Factor, Redox Titrations, Self Indicator & Miscellaneous Cases

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