In the balanced condition, the values of the resistances of the four arms of a Wheatstone bridge are shown in the figure below. The resistance R 3 has temperature coefficient 0.0004 ° C -1 . If the temperature of R 3 is increased by 100 ° C , the voltage developed between S and T will be \ \ \ \ volt.

Physics · Current Electricity

JEE Advanced 2020 — Paper 2 — Question 12

In the balanced condition, the values of the resistances of the four arms of a Wheatstone bridge are shown in the figure below. The resistance $\mathrm{R}_{3}$ has temperature coefficient $0.0004{ }^{\circ} \mathrm{C}^{-1}$ . If the temperature of $\mathrm{R}_{3}$ is increased by $100{ }^{\circ} \mathrm{C}$ , the voltage developed between S and T will be $\_\_\_\_$ volt.

Answer: 0.27

Numerical answer — enter this value.

Step-by-step solution

R'_3 = R_3(1 + \alpha \Delta T) = 312 \ \Omega

V_S - V_T = I_2 R_2 - I_1 R_1

= \frac{50}{100 + 500} \times 100 - \frac{50}{60 + 312} \times 60

\approx 0.2688 \approx 0.27 \ V

Answer key and solution verified before publishing.

Practise Current Electricity

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free

Exam: JEE Advanced 2020
Paper: Paper 2
Subject: Physics
Chapter: Current Electricity
Topic: Combination of Resistors and cells, Wheatstone Bridge