Physics · Atomic Physics

JEE Advanced 2020 — Paper 2 — Question 8

In an X-ray tube, electrons emitted from a filament (cathode) carrying current I hit a target (anode) at a distance d from the cathode. The target is kept at a potential V higher than the cathode resulting in emission of continuous and characteristic X-rays. If the filament current I is decreased to I2\frac{I}{2}, the potential difference VV is increased to 2V2 V, and the separation distance dd is reduced to d2\frac{d}{2}, then

  1. Option A:

    the cut-off wavelength will reduce to half, and the wavelengths of the characteristic X -rays will remain the same

    Correct
  2. Option B:

    the cut-off wavelength as well as the wavelengths of the characteristic X-rays will remain the same

  3. Option C:

    the cut-off wavelength will reduce to half, and the intensities of all the X -rays will decrease

    Correct
  4. Option D:

    the cut-off wavelength will become two times larger, and the intensity of all the X-rays will decrease

Answer: A, C

Step-by-step solution

λC∝1 V\lambda_{\mathrm{C}} \propto \frac{1}{\mathrm{~V}}, current ∝\propto Intensity

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2020
Paper
Paper 2
Subject
Physics
Chapter
Atomic Physics
Topic
X-Rays
In an X-ray tube, electrons emitted from a filament (cathode)… | JEE Advanced 2020 PYQ with Solution · DhiX AI