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Mathematics · Permutations and Combinations

JEE Advanced 2020 — Paper 2 — Question 47

In a hotel, four rooms are available. Six persons are to be accommodated in these four rooms in such a way that each of these rooms contains at least one person and at most two persons. Then the number of all possible ways in which this can be done is ____\_\_\_\_

Answer: 1080

Numerical answer — enter this value.

Step-by-step solution

Two rooms accommodate two persons each other two room have one person each.

Total ways 6!(2!)2(1!)22!2!×4!=1080\frac{6!}{(2!)^{2}(1!)^{2} 2!2!} \times 4!=1080

Answer key and solution verified before publishing.

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Exam
JEE Advanced 2020
Paper
Paper 2
Subject
Mathematics
Chapter
Permutations and Combinations
Topic
Applications of Permuations and Combination

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