Chemistry · Practical Inorganic chemistry (Qualitative Analysis)

JEE Advanced 2025 — Paper 2 — Question 33

During sodium nitroprusside test of sulphide ion in an aqueous solution, one of the ligands coordinated to the metal ion is converted to

Option A:
NOS
Correct
Option B:
$\mathrm{SCN}^{-}$
Option C:
$\mathrm{SNO}^{-}$
Option D:
NCS

Answer: A

Step-by-step solution

$\quad \mathrm{Na}_{2}\left[\mathrm{Fe}(\mathrm{CN})_{5}(\mathrm{NO})\right]+\mathrm{Na}_{2} \mathrm{~S} \rightarrow \mathrm{Na}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{5}(\mathrm{NOS})\right]$

Sodium nitroprusside purple solution

Answer key and solution verified before publishing.

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Exam: JEE Advanced 2025
Paper: Paper 2
Subject: Chemistry
Chapter: Practical Inorganic chemistry (Qualitative Analysis)
Topic: Identification of Anions