Consider the reaction sequence from P to Q shown below. The overall yield of the major product Q from P is 75 \% . What is the amount in grams of Q obtained from 9.3 mL of P ? (Use density of P =1.00 g mL -1 ; Molar mass of C =12.0, H =1.0, O =16.0 and N =14.0 g mol -1 )

Chemistry · Nitrogen Containing Organic Compounds

JEE Advanced 2020 — Paper 2 — Question 31

Consider the reaction sequence from $\mathbf{P}$ to $\mathbf{Q}$ shown below. The overall yield of the major product $\mathbf{Q}$ from $\mathbf{P}$ is

$75 \%$ . What is the amount in grams of $\mathbf{Q}$ obtained from 9.3 mL of $\mathbf{P}$ ? (Use density of $\mathbf{P}=1.00 \mathrm{~g} \mathrm{~mL}^{-1}$ ;

Molar mass of $\mathrm{C}=12.0, \mathrm{H}=1.0, \mathrm{O}=16.0$ and $\mathrm{N}=14.0 \mathrm{~g} \mathrm{~mol}^{-1}$ )

Answer: 18.6

Numerical answer — enter this value.

Step-by-step solution

Moles of $\mathrm{P}=\frac{9.3}{93}=0.1=$ moles of Q .

So, mass of $(Q)=0.1 \times 248 \times 0.75=18.60$ gram

Answer key and solution verified before publishing.

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Exam: JEE Advanced 2020
Paper: Paper 2
Subject: Chemistry
Chapter: Nitrogen Containing Organic Compounds
Topic: Aniline