JEE Advanced 2025 — Paper 2 — Question 42

At 300 K , an ideal dilute solution of a macromolecule exerts osmotic pressure that is expressed in terms of the height (h) of the solution (density $=1.00 \mathrm{~g} \mathrm{~cm}^{-3}$ ) where h is

equal to 2.00 cm . If the concentration of the dilute solution of the macromolecule is $2.00 \mathrm{~g} \mathrm{dm}^{-3}$, the molar mass of the macromolecule is calculated

to be ${X} \times 10^{4} \mathrm{~g} \mathrm{~mol}^{-1}$.

The value of ${X}$ is $\qquad$ . Use : Universal gas constant $(\mathrm{R})=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$ and acceleration due to gravity $(\mathrm{g})=10 \mathrm{~m} \mathrm{~s}^{-2}$