Chemistry · Structure of Atom

JEE Advanced 2024 — Paper 1 — Question 36

Among the following, the correct statement(s) for electrons in an atom is(are)

Option A:
Uncertainty principle rules out the existence of definite paths for electrons.
Correct
Option B:
The energy of an electrons in 2 s orbital of an atom is lower than the energy of an electron that is infinitely far away from the nucleus
Correct
Option C:
According to Bohr's model, the most negative energy value for an electron is given by $\mathrm{n}=1$ , which corresponds to the most stable orbit.
Correct
Option D:
According to Bohr's model, the magnitude of velocity of electrons increases with increase in values of $n$ .\end{itemize}

Answer: A, B, C

A) uncertainty principle rules - out the existence of definite paths for an electron due to wave nature of electron.

B) Energy $\propto-\frac{Z^{2}}{n^{2}}$ So, $\mathrm{E}_{2 \mathrm{~s}}<\mathrm{E}_{\infty}$

(C) $E=-\frac{13.6 \times Z^{2}}{n^{2}}$ If $n=1$ $E=-\left(13.6 \times Z^{2}\right) e V$ is most negative value and therefore most stable.

(D) $V=2.186 \times 10^{6} \times \frac{Z}{n}$

Answer key and solution verified before publishing.

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